**This blog is about Clever Questions, Answers, Resources, Links, Discussions, Tips about jobs and careers at FAANGM companies: Facebook, Apple, Amazon, AWS, Netflix, Google, Microsoft, Linkedin**

**2. How to prepare for FAANGM jobs interviews**

You must be able to write code. It is as simple as that. Prepare for the interview by practicing coding exercises in different categories. You’ll solve one or more coding problems focused on CS fundamentals like algorithms, data structures, recursions, and binary trees.

**Coding Interview Tips**

These tips from FAANGM engineers can help you do your best.

**Make sure you understand the question. Read it back to your interviewer. Be sure to ask any clarifying questions. **

**An interview is a two-way conversation; feel free to be the one to ask questions, too.**

**Don’t rush. Take some time to consider your approach. For example, on a tree question, you’ll need to choose between an iterative or a recursive approach. It’s OK to first use a working, unoptimized solution that you can iterate on later. **

**Talk through your thinking and processes out loud. This can feel unnatural; be sure to practice it before the interview.**

**Test your code by running through your problem with a few test and edge cases. Again, talk through your logic out loud when you walk through your test cases.**

**Think of how your solution could be better, and try to improve it. When you’ve finished, your interviewer will ask you to analyze the complexity of the code in Big O notation. **

**Walk through your code line by line and assign a complexity to each line.**

**Remember how to analyze how “good” your solution is: how long does it take for your solution to complete? Watch this video to get familiar with Big O Notation.**

**How to Approach Problems During Your Interview**

**Before you code**

• **Ask clarifying questions. Talk through the problem and ask follow-up questions to make sure you understand the exact problem you’re trying to solve before you jump into buildingthe solution.**

•

**Let us know if you’ve seen the problem previously. That will help us understand your context.**

•

**Present multiple potential solutions, if possible. Talk through which solution you’re choosing and why.**

**While you code**

• **Don’t forget to talk! While your tech screen will focus heavily on coding, the engineer you’re interviewing with will also be evaluating your thought process.** Explaining your decisions and actions as you go will help the interviewer understand your choices.

• **Be flexible. **Some problems have elegant solutions, and some must be brute forced.

If you get stuck, just describe your best approach and ask the interviewer if you should go that route. It’s much better to have non-optimal but working code than just an idea with nothing written down.

• **Iterate rather than immediately trying to jump to the clever solution.** If you can’t explain your concept clearly in five minutes, it’s probably too complex.

• **Consider (and be prepared to talk about):**

•** Different algorithms and algorithmic techniques, such as sorting, divide-and-conquer, recursion, etc.**

• **Data structures, particularly those used most often (array, stack/queue, hashset/hashmap/hashtable/dictionary, tree/binary tree, heap, graph, etc.)**

• **O memory constraints on the complexity of the algorithm you’re writing and its running time as expressed by big-O notation.**

• **Generally, avoid solutions with lots of edge cases or huge if/else if/else blocks, in most cases. Deciding between iteration and recursion can be an important step**

**After you code**

• **Expect questions.** The interviewer may tweak the problem a bit to test your knowledge and see if you can come up with another answer and/or further optimize your solution.

• **Take the interviewer’s hints to improve your code.** If the interviewer makes a suggestion or asks a question, listen fully so you can incorporate any hints they may provide.

• **Ask yourself if you would approve your solution as part of your codebase.** Explain your answer to your interviewer. Make sure your solution is correct and efficient, that you’ve taken into account edge cases, and that it clearly reflects the ideas you’re trying to express in your code.

**3- FAANGM Screening/Phone Interview Examples:**

**Arrays**

**Reverse to Make Equal**: Given two arrays **A** and **B** of length N, determine if there is a way to make **A** equal to **B** by reversing any subarrays from array **B** any number of times. **Solution here**

**Contiguous Subarrays**: You are given an array **arr** of **N** integers. For each index **i**, you are required to determine the number of contiguous subarrays that fulfills the following conditions:

The value at index i must be the maximum element in the contiguous subarrays, and

These contiguous subarrays must either start from or end on index i. **Solution here**

**Add 2 long integer** (Example: “1001202033933333093737373737” + “934019393939122727099000000”) **Solution here**

# Python3 program to find sum of

# two large numbers.

```
```# Function for finding sum of

# larger numbers

def findSum(str1, str2):

# Before proceeding further,

# make sure length of str2 is larger.

if (len(str1) > len(str2)):

t = str1;

str1 = str2;

str2 = t;

# Take an empty string for

# storing result

str = "";

# Calculate length of both string

n1 = len(str1);

n2 = len(str2);

# Reverse both of strings

str1 = str1[::-1];

str2 = str2[::-1];

carry = 0;

for i in range(n1):

# Do school mathematics, compute

# sum of current digits and carry

sum = ((ord(str1[i]) - 48) +

((ord(str2[i]) - 48) + carry));

str += chr(sum % 10 + 48);

# Calculate carry for next step

carry = int(sum / 10);

# Add remaining digits of larger number

for i in range(n1, n2):

sum = ((ord(str2[i]) - 48) + carry);

str += chr(sum % 10 + 48);

carry = (int)(sum / 10);

# Add remaining carry

if (carry):

str += chr(carry + 48);

# reverse resultant string

str = str[::-1];

return str;

# Driver code

str1 = "12";

str2 = "198111";

print(findSum(str1, str2));

# This code is contributed by mits

### Optimized version below

# python 3 program to find sum of two large numbers.

```
```# Function for finding sum of larger numbers

def findSum(str1, str2):

# Before proceeding further, make sure length

# of str2 is larger.

if len(str1)> len(str2):

temp = str1

str1 = str2

str2 = temp

# Take an empty string for storing result

str3 = ""

# Calculate length of both string

n1 = len(str1)

n2 = len(str2)

diff = n2 - n1

# Initially take carry zero

carry = 0

# Traverse from end of both strings

for i in range(n1-1,-1,-1):

# Do school mathematics, compute sum of

# current digits and carry

sum = ((ord(str1[i])-ord('0')) +

int((ord(str2[i+diff])-ord('0'))) + carry)

str3 = str3+str(sum%10 )

carry = sum//10

# Add remaining digits of str2[]

for i in range(n2-n1-1,-1,-1):

sum = ((ord(str2[i])-ord('0'))+carry)

str3 = str3+str(sum%10 )

carry = sum//10

# Add remaining carry

if (carry):

str3+str(carry+'0')

# reverse resultant string

str3 = str3[::-1]

return str3

# Driver code

if __name__ == "__main__":

str1 = "12"

str2 = "198111"

print(findSum(str1, str2))

# This code is contributed by ChitraNayal

**Strings**

**Rotational Cipher**: One simple way to encrypt a string is to “rotate” every alphanumeric character by a certain amount. Rotating a character means replacing it with another character that is a certain number of steps away in normal alphabetic or numerical order.For example, if the string “Zebra-493?” is rotated 3 places, the resulting string is “Cheud-726?”. Every alphabetic character is replaced with the character 3 letters higher (wrapping around from Z to A), and every numeric character replaced with the character 3 digits higher (wrapping around from 9 to 0). Note that the non-alphanumeric characters remain unchanged.Given a string and a rotation factor, return an encrypted string. **Solution here**

Matching Pairs: Given two strings **s** and **t** of length **N**, find the maximum number of possible matching pairs in strings **s** and **t** after swapping exactly two characters within **s**.A swap is switching **s**[**i**] and **s**[**j**], where **s**[**i**] and **s**[**j**] denotes the character that is present at the **i**th and **j**th index of **s**, respectively. The matching pairs of the two strings are defined as the number of indices for which **s**[**i**] and **t**[**i**] are equal. Note: This means you **must** swap two characters at different indices. **Solution here**

**Minimum Length Substrings**: You are given two strings s and t. You can select any substring of string s and rearrange the characters of the selected substring. Determine the minimum length of the substring of s such that string t is a substring of the selected substring. **Solution here**

**Recursion**

**Encrypted Words**: You’ve devised a simple encryption method for alphabetic strings that shuffles the characters in such a way that the resulting string is hard to quickly read, but is easy to convert back into the original string.

When you encrypt a string S, you start with an initially-empty resulting string R and append characters to it as follows:

Append the middle character of S (if S has even length, then we define the middle character as the left-most of the two central characters)

Append the encrypted version of the substring of S that’s to the left of the middle character (if non-empty)

Append the encrypted version of the substring of S that’s to the right of the middle character (if non-empty)

For example, to encrypt the string “abc”, we first take “b”, and then append the encrypted version of “a” (which is just “a”) and the encrypted version of “c” (which is just “c”) to get “bac”.

If we encrypt “abcxcba” we’ll get “xbacbca”. That is, we take “x” and then append the encrypted version “abc” and then append the encrypted version of “cba”.

**Greedy Algorithms**

**Slow Sums**: Suppose we have a list of **N** numbers, and repeat the following operation until we’re left with only a single number: Choose any two numbers and replace them with their sum. Moreover, we associate a penalty with each operation equal to the value of the new number, and call the penalty for the entire list as the sum of the penalties of each operation.For example, given the list **[1, 2, 3, 4, 5]**, we could choose **2 and 3** for the first operation, which would transform the list into **[1, 5, 4, 5]** and incur a penalty of **5**. The goal in this problem is to find the **worst** possible penalty for a given input.

**Linked Lists**

**Reverse Operations**: You are given a singly-linked list that contains **N** integers. A *subpart* of the list is a contiguous set of even elements, bordered either by either end of the list or an odd element. For example, if the list is [1, 2, 8, 9, 12, 16], the *subparts* of the list are [2, 8] and [12, 16].Then, for each subpart, the order of the elements is reversed. In the example, this would result in the new list, [1, 8, 2, 9, 16, 12].The goal of this question is: given a resulting list, determine the original order of the elements. **Solution Here.**

**Hash Tables**

**Pair Sums:** Given a list of n integers arr[0..(n-1)], determine the number of different pairs of elements within it which sum to k. If an integer appears in the list multiple times, each copy is considered to be different; that is, two pairs are considered different if one pair includes at least one array index which the other doesn’t, even if they include the same values. **Solution here.**

**Note: These exercises assume you have knowledge in coding but not necessarily knowledge of binary trees, sorting algorithms, or related concepts.**

• **Topic 1 | Arrays & Strings**

• **A Very Big Sum**

• **Designer PDF Viewer**

• **Left Rotation**

### A very big Sum in Java

import java.io.*;

import java.util.*;

import java.text.*;

import java.math.*;

import java.util.regex.*;

```
```public class Solution {

` /**`

* Your solution in here. Just need to add the number in a variable type long so you

* don't face overflow.

*/

static long aVeryBigSum(int n, long[] ar) {

long sum = 0;

for (int i = 0; i < n; i++) {
sum += ar[i];
}
return sum;
}
/**
* HackerRank provides this code.
*/
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
long[] ar = new long[n];
for(int ar_i = 0; ar_i < n; ar_i++){
ar[ar_i] = in.nextLong();
}
long result = aVeryBigSum(n, ar);
System.out.println(result);
}
}

### Left Rotation in Java

import java.io.*;

import java.util.*;

import java.text.*;

import java.math.*;

import java.util.regex.*;

```
```public class Solution {

static int[] leftRotation(int[] a, int d) {

// They say in requirements that these inputs should not be considered.

// However, noting that we should prevent against those.

if (d == 0 || a.length == 0) {

return a;

}

int rotation = d % a.length;

if (rotation == 0) return a;

// Please note that there is an implementation, circular arrays that could be considered here,

// but that one has an edge case (Test#1)

// As, we don't need to optimize for memory, let's keep it simple.

int [] b = new int[a.length];

for (int i = 0; i < a.length; i++) {
b[i] = a[indexHelper(i + rotation, a.length)];
}
return b;
}
/**
* Takes care of the case where the rotation index. You have to take into account
* how it is rotated towards the left. To compute index of B, we rotate towards the right.
* If we were to do a[i] in the loop, then these method would need to be slightly chnaged
* to compute index of b.
*/
private static int indexHelper(int index, int length) {
if (index >= length) {

return index - length;

} else {

return index;

}

}

` public static void main(String[] args) {`

Scanner in = new Scanner(System.in);

int n = in.nextInt();

int d = in.nextInt();

int[] a = new int[n];

for(int a_i = 0; a_i < n; a_i++){
a[a_i] = in.nextInt();
}
int[] result = leftRotation(a, d);
for (int i = 0; i < result.length; i++) {
System.out.print(result[i] + (i != result.length - 1 ? " " : ""));
}
System.out.println("");
in.close();
}
}

### Sparse Array in Java

import java.io.*;

import java.util.*;

```
```public class Solution {

public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);

final int totalN = Integer.parseInt(scanner.nextLine());

final Map mapWords = buildCollectionOfStrings(scanner, totalN);

final int numberQueries = Integer.parseInt(scanner.nextLine());

printOcurrenceOfQueries(scanner, numberQueries, mapWords);

}

` /**`

* This method construcs a map with the collection of Strings and occurrence.

*/

private static Map

final Map

for (int i = 0; i < n; i++) {
final String line = scanner.nextLine();
if (map.containsKey(line)) {
map.put(line, map.get(line) + 1);
} else {
map.put(line, 1);
}
}
return map;
}
private static void printOcurrenceOfQueries(Scanner scanner, int numberQueries, Map

for (int i = 0; i < numberQueries; i++) {
// for each query, we look for how many times it occurs and we print on screen the value.
final String line = scanner.nextLine();
if (mapWords.containsKey(line)) {
System.out.println(mapWords.get(line));
} else {
System.out.println(0);
}
}
}
}

• **Topic 2 | Lists**

** Insert a Node at a Position Given in a List****Cycle Detection**

• **Topic 3 | Stacks & Queues**

**Balanced Brackets****Queue Using Two Stacks**

• **Topic 4 | Hash & Maps**

**Ice Cream Parlor****Colorful Number**

• **Topic 5 | Sorting Algorithms**

**Insertion Sort part 2****Quicksort part 2**

• **Topic 6 | Trees**

**Binary Tree Insertion****Height of a Binary Tree****Qheap1**

• **Topic 7 | Graphs (BFS & DFS)**

**Breath First Search****Snakes and Ladders**

• **Topic 8 | Recursion**

**Solutions:** **All solutions are available in this public repository**:

4**- FAANGM Interview Tips**

**What they usually look for:**

**The interviewer will be thinking about how your skills and experience might help their teams. **

Help them understand the value you could bring by focusing on these traits and abilities.

• **Communication**: Are you asking for requirements and clarity when necessary, or are you

just diving into the code? Your initial tech screen should be a conversation, so don’t forget

to ask questions.

• **Problem solving**: They are evaluating how you comprehend and explain complex ideas. **Are you providing the reasoning behind a particular solution? Developing and comparing multiple solutions? Using appropriate data structures? Speaking about space and time complexity?** **Optimizing your solution?**

• **Coding.** Can you convert solutions to executable code? Is the code organized and does it

capture the right logical structure?

• **Verification.** Are you considering a reasonable number of test cases or coming up with a

good argument for why your code is correct? If your solution has bugs, are you able to walk

through your own logic to find them and explain what the code is doing?

- **Please review Amazon Leadership Principles, to help you understand Amazon's culture and assess if it's the right environment for you** (**For Amazon**)

- **Review the STAR interview technique** (**All**)

5- **FAANGM Compensation**

**Legend - Base / Stocks (Total over 4 years) / Sign On**

**Google**

- 105/180/22.5 (2016, L3)

- 105/280/58 (2016, L3)

- 105/330/22.5 (2016, L3)

- 110/180/25 (2016, L3)

- 110/270/30 (2016, L3)

- 110/250/20 (2016, L3)

- 110/160/70 (2016, L3)

- 112/180/50 (2016, L3)

- 115/180/50 (2016, L3)

- 140/430/50 (2016, L3)

- 110/90/0 (2017, L3)

- 145/415/100 (2017, L3)

- 120/220/25 (2018, L3)

- 145/270/30 (2017, L4)

- 150/400/30 (2018, L4)

- 155/315/50 (2017, L4)

- 155/650/50 (2017, L4)

- 170/350/50 (2017, L4)

- 170/400/75 (2017, L4)

***Google's target annual bonus is 15%. Vesting is monthly and has no cliff.**

**Facebook**

- 105/120/120 (2016, E3)

- 105/150/75 (2016, E3)

- 105/100/50 (2016, E3)

- 105/240/105 (2016, E3)

- 107/150/75 (2016, E3)

- 110/150/75 (2016, E3)

- 110/235/75 (2016, E3)

- 115/150/75 (2016, E3)

- 110/150/110 (2017, E3)

- 115/160/100 (2017, E3)

- 160/300/70 (2017, E4)

- 145/220/0 (2017, E4)

- 160/300/100 (2017, E4)

- 160/300/100 (2017, E4)

- 150/250/25 (2017, E4)

- 150/250/60 (2017, E4)

- 175/250/0 (2017, E5)

- 160/250/100 (2018, E4)

- 170/450/65 (2015, E5)

- 180/600/50 (2016, E5)

- 180/625/50 (2016, E5)

- 170/500/100 (2017, E5)

- 175/450/50 (2017, E5)

- 175/480/75 (2017, E5)

- 190/600/70 (2017, E5)

- 185/600/100 (2017, E5)

- 185/1000/100 (2017, E5)

- 190/500/120 (2017, E5)

- 200/550/50 (2018, E5)

- 210/1000/100 (2017, E6)

***Facebook's target annual bonus is 10% for E3 and E4. 15% for E5 and 20% for E6. Vesting is quarterly and has no cliff.**

**LinkedIn** (Microsoft)

- 125/150/25 (2016, SE)

- 120/150/10 (2016, SE)

- 170/300/30 (2016, Senior SE)

- 140/250/50 (2017, Senior SE)

**Apple**

- 110/60/40 (2016, ICT2)

- 140/99/8 (2016, ICT3)

- 140/100/20 (2016, ICT3)

- 155/130/65 (2017, ICT3)

- 120/100/21 (2017, ICT3)

- 135/105/20 (2017, ICT3)

- 160/105/30 (2017, ICT4)

**Amazon**

- 95/52/47 (2016, SDE I)

- 95/53/47 (2016, SDE I)

- 95/53/47 (2016, SDE I)

- 100/70/59 (2016, SDE I)

- 103/65/52 (2016, SDE I)

- 103/65/40 (2016, SDE I)

- 103/65/52 (2016, SDE I)

- 110/200/50 (2016, SDE I)

- 135/70/45 (2016, SDE I)

- 106/60/65 (2017, SDE I)

- 130/88/62 (2016, SDE II)

- 127/94/55 (2017, SDE II)

- 152/115/72 (2017, SDE II)

- 160/160/125 (2017, SDE II)

- 178/175/100 (2017, SDE II)

- 145/120/100 (2018, SDE II)

- 160/320/185 (2018, SDE III)

***Amazon stocks have a 5/15/40/40 vesting schedule and sign on is split almost evenly over the first two years***

**Microsoft**

- 100/25/25 (2016, SDE)

- 106/120/20 (2016, SDE)

- 106/60/20 (2016, SDE)

- 106/60/10 (2016, SDE)

- 106/60/15 (2016, SDE)

- 106/60/15 (2016, SDE)

- 106/120/15 (2016, SDE)

- 107/90/35 (2016, SDE)

- 107/120/30 (2017, SDE)

- 110/50/20 (2016, SDE)

- 119/25/15 (2017, SDE)

**Twitter**

- 130/200/20 (2016, SWE1)

- 120/150/18.5 (2016, SWE1)

- 145/125/15 (2017, SWE1)

- 160/600/50 (2017, SWE II)

**Uber**

- 110/180/0 (2016, L3)

- 110/150/0 (2016, L3)

- 140/590/0 (2017, L4)

**Lyft**

- 135/260/60 (2017, L3)

- 170/720/20 (2017, L4)

- 152/327/0 (2017, L4)

- 175/480/0 (2017, L4)

**Dropbox**

- 167/464/10 (2017, IC2)

- 160/250/10 (2017, IC2)

- 160/300/50 (2017, IC2)

**6. Top-paying Cloud certifications for FAANGM:**

- Google Certified Professional Cloud Architect — $175,761/year
- AWS Certified Solutions Architect – Associate — $149,446/year
- Azure/Microsoft Cloud Solution Architect - $141,748/yr
- Google Cloud Associate Engineer - $145,769/yr
- AWS Certified Cloud Practitioner — $131,465/year
- Microsoft Certified: Azure Fundamentals — $126,653/year
- Microsoft Certified: Azure Administrator Associate — $125,993/year

**According to the 2020 **Global Knowledge report**, the top-paying cloud certifications for the year are (drumroll, please):**

**7- FAANGM FAQ (Frequently Asked Questions and Answers)**

**Does any of the FANG offer internship to self taught programmers?**

I am not a lawyer, but I believe there is some sort of legal restrictions on what an internship can be (in California, at least). In my previous company, we had discussed cases on whether or not someone who was out of school can be an intern, and we got an unequivocal verdict that you have to be in school, or about to start school (usually college or graduate school, but high school can work too), in order to be considered for an internship.

I suspect the reason for this is to protect a potential intern from exploitation by companies who would offer temporary jobs to people while labeling them as learning opportunities in order to pay less.

Personally, I feel for people like you, in an ideal world you should be allowed to have the same opportunities as the formally schooled people, and occasionally there are. For example, some companies offer residency programs which are a bit similar to internships. In many cases, though, these are designed to help underrepresented groups. Some examples include:

**Facebook’s The Artificial Intelligence (AI) Residency Program**

**Google’s Eng Residency**

**Microsoft AI Residency Program**

**How can I get an intership as a product manager at faang or any other tech company?**

**What questions to expect in cloud support engineer deployment roles at AWS?**

Recipes to succeed in corporate, how to navigate the job world.

**Ever wonder how the FAANGM big tech make their money?**

This is a common bug in the thinking of people, doing the wrong thing *harder* in the hope that it works this time. Asking t*ough* questions is like hitting a key harder when the broken search function in LinkedIn fails. No matter how hard you hit the key, it won’t work.

Given the low quality of the LinkedIn platform from a technical perspective it seems hard to imagine that they hire the best or even the mediocre. But it may be that because their interviews are *too* tough to hire good programmers.

Just because so few people can get a question right, does not mean it is a *good* question, merely that it is tough. I am also a professional software developer and know a bunch of algorithms, but also am wholly ignorant of many others. Thus it is easy to ask me (or anyone else) questions they can’t answer. I am (for instance) an expert on sort/merging, and partial text matching, really useful for big data, wholly useless for UX.

So if you ask about an obscure algorithm or brain teaser that is too hard you don’t measure their ability, but their luck in happening to know that algo or having seen the answer to a puzzle. More importantly how likely are they to need it ?

This is a tricky problem for interviewers, if you know that a certain class of algorithms are necessary for a job, then if you’re a competent s/w dev manager then odds are that you’ve already put them in and they just have to integrate or debug them. Ah, so I’ve now given away one of *my* interview techniques. We both know that debugging is more of our development effort than writing code. Quicksort (for instance) is conceptually quite easy being taught to 16 year old Brits or undergraduate Americans, but it turns out that some implementations can go quadratic in space and/or time complexity and that comparison of floating point numbers is a sometimes thing and of course some idiot may have put = where he should have put == or >= when > is appropriate.

Resolving that is a better test, not complete of course, but better.

For instance I know more about integrating C++ with Excel than 99.9% of programmers. I can ask you why there are a whole bunch of INT 3’s laying around a disassembly of Excel, yes I have disassembled Excel, and yes my team was at one point asked to debug the damned thing for Microsoft. I can ask about LSTRs, and why SafeArrays are in fact really dangerous. I can even ask you how to template them. That’s not easy, trust me on this.

Are you impressed by my knowledge of this ?

I sincerely hope not.

Do you think it would help me build a competent search engine, something that the coders at LinkedIn are simply unable to do ?

No.

I also know a whole bunch of numerical methods for solving PDEs. Do you know what a PDE even is ? This can be really hard as well. Do you care if you can’t do this ? Again not relevant to fixing the formless hell of LI code. fire up the developer mode of your browser and see what it thinks of Linkedin’s HTML, I’ve never seen a debugger actually vomit in my face before.

A *good *interview is a measure not just of ability but of the precise set of skills you bring to the team. A good interviewer is not looking for the best, but the best fit.

Sadly some interviewers see it as an ego thing that they can ask hard questions. So can I, but it’s not my job. My job is identfying those that can deliver most, *hard* questions that you can’t answer are far less illuminating that questions you struggle with because I get to see the quality of your thinking in terms of complexity, insight, working with incomplete and misleading information and determination not to give up because it is going badly.

Do you as a candidate ask questions well ? If I say something wrong, do you a) notice, b) have the soft skills to put it to me politely, c) have the courage to do so ?

*Courage* is an under-rated attribute that superior programmers have and failed projects have too little of.

Yes, some people have too much courage, which is a deeper point, where for many things there is an optimum amount and the right mix for your team at this time. I once had to make real time un-reversible changes to a *really* important database whilst something very very bad happened on TV news screens above my head. Too much or too little bravery would have had consequences. Most coding ain’t that dramatic, but the superior programmer has *judgement*, when to try the cool new language/framework feature in production code, when to optimise for speed, or for space and when for never ever crashes even when memory is corrupted by external effects. When does portability matter or not ? Some code will only be used once and we both know some of it will literally never be executed in live, do we obsess about it’s quality in terms of performance and maintainability .

The right answer is *it depends*, and that is a lot more important to hiring the best than curious problems in number theory or O(N Log(N)) for very specific code paths that rarely execute.

Also programming is a marathon, not a sprint, or perhaps more like a long distance obstacle course, stretches of plodding along with occasional walls. Writing a better search engine than LinkedIn “programmers” manage is a wall, I know this because my (then) 15 year old son took several weeks, at 15, he was only 2 or 3 times better than the best at LinkedIn, but he’s 18 now and as a professional grade programmer, him working for LinkedIn would be like putting the head of the Vulcan Science Academy in among a room of Gwyneth Paltrow clones.

And that ultimately may be the problem.

Good people have more options and if you have a bad recruitment process then they often will reject your offer. We spend more of our lives with the people we work with than sleep with and if at interview management is seen as pompous or arrogant then they won’t get the best people.

There’s now a Careers advice space on Quora, you might find it interesting.

**8- Resources:**

- **Cracking the Coding Interview: 189 Programming Questions and Solutions**

**Top sites for practice problems:**

• **Facebook Sample Interview Problems and Solutions**

• **InterviewBit**

• **LeetCode**

• **HackerRank**

**Video prep guides for tech interviews:**

• **Cracking the Facebook Coding Interview: The Approach** (The password is FB_IPS)

• **Cracking the Facebook Coding Interview: Problem Walk-through** (The password is FB_IPS)

**Additional resources*:**

•** I Interviewed at Five Top Companies in Silicon Valley in Five Days, and Luckily GotFive Job Offers**